#include <iostream>
#include <iomanip>
using namespace std;

int main() {
    int n;
    // 读取甲带的金额
    cin >> n;
    // 计算乙带的金额
    int moneyB = n + 8;
    // 计算丙带的金额
    int moneyC = moneyB - 2;
    // 计算平均值
    double average = (n + moneyB + moneyC) / 3.0;
    // 输出结果
    cout << n << endl;
    cout << moneyB << endl;
    cout << moneyC << endl;
    cout << fixed << setprecision(1) << average << endl;
    return 0;
}
    
/**************************************************************
	Problem: 1612
	User: fuyijun
	Language: C++
	Result: Accepted
	Time:7 ms
	Memory:2072 kb
****************************************************************/