import math
def suShu(n):
    f = True
    for i in range (2, int(math.sqrt(n))+1):
        if n % i == 0:
            f = False; 
    return f and n != 1
    
n = int(input())
f = False;
for a in range(2,int(math.sqrt(n))+1):
        for b in range (int(math.sqrt(n))+1, n ):
                if n == a * b and suShu(a) and suShu(b):
                    f = True;
if f:
     print("It's a Tongtong number.")
else:
     print("It's not a Tongtong number.")


/**************************************************************
	Problem: 1151
	User: admin
	Language: Python
	Result: Accepted
	Time:100 ms
	Memory:34480 kb
****************************************************************/