n = int(input())
m = input().split()
l = []
mi = 0
su = 0
c = 0
#列表类型转换
for v in m:
    l.append(int(v))
#求列表最小值
mi = min(l)
#遍历l列表,把列表中等于最小值的元素去掉,得出余下的值的和
for i in range(0, n):
    if l[i] != mi:
        su += l[i]
        c += 1
print('%.1f' % (su / c))
/**************************************************************
	Problem: 1218
	User: admin
	Language: Python
	Result: Accepted
	Time:196 ms
	Memory:34480 kb
****************************************************************/