# -*- coding: utf-8 -*-
import sys

class BTree:
    '''
    Represent a no in a binary tree.
    '''
    def __init__(self, c='/0', l=None, r=None):
        '''
        Initializes the node's data
        '''
        self.e = c
        self.left = l
        self.right = r
        
def preorderTraverse(bt):
    '''
    返回前序遍历结果
    '''
    if bt:
        return '%s%s%s' % (bt.e, preorderTraverse(bt.left), preorderTraverse(bt.right))
    return ''
def inorderTraverse(bt):
    '''
    返回中序遍历结果
    '''
    if bt:
        return '%s%s%s' % (inorderTraverse(bt.left), bt.e, inorderTraverse(bt.right))
    return '';
def postorderTraverse(bt):
    '''
    返回后序遍历结果
    '''
    if bt:
        return '%s%s%s' % (postorderTraverse(bt.left), postorderTraverse(bt.right), bt.e)
    return ''
def printBTree(bt, depth):
    '''
    递归打印这棵二叉树，*号表示该节点为NULL
    '''
    '''
    if not bt:
        ch = '*'
    else:
        ch = bt.e
    '''
    #ch=(lambda x: (x and x.e) or '*')(bt)
    ch = bt.e if bt else '*'
    if(depth > 0):
        print '%s%s%s' % ((depth - 1) * '  ', '--', ch)
    else:
        print ch
    if not bt:
        return
    printBTree(bt.left, depth + 1)
    printBTree(bt.right, depth + 1)
def buildBTreeFromPreIn(preo, ino):
    '''
    根据前序和中序遍历结果重构这棵二叉树
    '''
    if(preo == '' or ino == ''):
        return None
    pos = ino.find(preo[0])
    if(pos < 0):
        return None        
    return BTree(preo[0], buildBTreeFromPreIn(preo[1:pos + 1], ino[0:pos]), buildBTreeFromPreIn(preo[pos + 1:], ino[pos + 1:]))
   
for line in sys.stdin:
      preo,ino = line.split()
      #print preo,ino
      bt = buildBTreeFromPreIn(preo, ino)
      print postorderTraverse(bt)
/**************************************************************
	Problem: 2121
	User: admin
	Language: Python
	Result: Wrong Answer
****************************************************************/