# 因为零件有 100 多个，所以从 101 开始遍历
for num in range(101, 200):
    # 判断是否满足三个三个数剩二个
    if num % 3 == 2:
        # 判断是否满足五个五个数剩三个
        if num % 5 == 3:
            # 判断是否满足七个七个数剩五个
            if num % 7 == 5:
                # 若都满足条件，输出该数并终止循环
                print(num)
                break
/**************************************************************
	Problem: 1017
	User: a99344
	Language: Python
	Result: Accepted
	Time:42 ms
	Memory:34244 kb
****************************************************************/